x²-5x-2011=0,x²-5x=2011
[(x-2)³-(x-1)²+1]/(x-2)?
=[(x-2)³+1-(x-1)²]/(x-2)
=[(x-2)³+(1+x-1)(1-x+1)]/(x-2)
=[(x-2)³+x(2-x)]/(x-2)
=[(x-2)³-x(x-2)]/(x-2)
=(x-2)²-x
=x²-4x+4-x
=x²-5x+4
=2011+4
=2015