> 数学 >
数学函数化简的问题!~~~~
(x-3)/(x+3)(x-1)怎么化简并求出值域?是要用到不等式来做
人气:454 ℃ 时间:2020-06-16 13:28:58
解答
(X-3)/(X+3)(X-1)
=(X-3)/[(X-3)^2+8(X-3)+12]
=1/[(X-3)+8+1/(X-3)]
当X>3时
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版