1/(1*2*3)+1/(2*3*4)+1/(3*4*5)+...+1/(9*10*11)简便运算
人气:482 ℃ 时间:2020-02-02 02:32:36
解答
1/(1*2*3)+1/(2*3*4)+1/(3*4*5)+...+1/(9*10*11)=1/2[1/(1×2)-1/(2×3)+1/(2×3)-1/(3×4)+...+1/(9×10)-1/(10×11)]=1/2×[1/(1×2)-1/(10×11)]=1/2×(1/2-1/110)=1/2×54/110=27/110 公式:1/n(n+1)(n+...
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