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m+3分之m减m的平方-9分之6再除以m减3分之2
人气:422 ℃ 时间:2019-10-23 11:29:53
解答
[m/(m+3)-6/(m^2-9)]÷[2/(m-3)]
=[m/(m+3)-6/(m+3)(m-3)]×[(m-3)/2]
={[m(m-3)-6]/[(m+3)(m-3)]}×[(m-3)/2]
=(m^2-3m-6)(m-3)/[2(m+3)(m-3)]
=(m^2-3m-6)/(2m+6)
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