极限的.计算limx→正无穷[x arctanx-(π/2)x]_数学解答

极限的.计算limx→正无穷[x arctanx-(π/2)x]

人气：293 ℃　时间：2020-02-01 00:07:53

解答

lim(x-> ∞) [xarctanx-(π/2)x]
=lim(x-> ∞) [arctanx -π/2] /(1/x) (0/0)
=lim(x-> ∞) [1/(1+x^2)] /(-1/x^2)
=0