∵y=cot(1/x)∴y'=x^(-2)csc^2(1/x)y=x^2sin(1/x)y'=2xsin(1/x)-cos(1/x)y=ln[ln(lnx)]y'=[1/ln(lnx)][ln(lnx)]'={1/[lnxln(lnx)]}(lnx)'=1/[xlnxln(lnx)]y=lnsin(x/2)y'=[1/sin(x/2)][sin(x/2)]'=(1/2)cos(x/2)/sin...