ace-bda=760
则①e=a,c-d=6,a-b=7 ②e=a,10+c-d=6,a-b-1=7
①显然,c=d+6>=6,a=e=b+7>=7
abcde能被9整除,则a+b+c+d+e=3a+2c-13=9n
20=7*3+2*6-13=8
a+b+c+d+e=3a+2d-12=9n
20=8*3+4*2-12