已知a^2+a-1=0,求2a^3+4a^2+2的值;求(a-1/a)^2
人气:470 ℃ 时间:2020-05-07 13:10:29
解答
a^2+a-1=0,所以a^2+a = 1
2a^3+4a^2+2
= 2a (a^2 + 2a) +2
= 2a (1 + a) + 2
= 2 (a + a^2) + 2
= 4
a^2+a-1=0,所以a^2 - 1 = a
(a-1/a)^2
= [(a^2 - 1)/a]^2
= [a/a]^2
= 1
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