(2²+1)(2的4次幂+1)(2的8次幂+1)(2的16次幂+1)(2²-1)_数学解答

(2²+1)(2的4次幂+1)(2的8次幂+1)(2的16次幂+1)(2²-1)

人气：170 ℃　时间：2020-03-13 13:26:49

解答

(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^2-1)
=(2^2+1)(2^2-1)(2^4+1)(2^8+1)(2^16+1)
=(2^4-1)(2^4+1)(2^8+1)(2^16+1)
=(2^8-1)(2^8+1)(2^16+1)
=(2^16-1)(2^16+1)
=2^32-1