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(cos^2)15°-(sin^2)15等于多少
人气:496 ℃ 时间:2020-02-05 03:40:55
解答
这是因为:方法一:(cos^2)15°-(sin^2)15=(cos15+sin15)(cos15-sin15)=[sin(90-15)+sin15][sin(90-15)-sin15]=(sin75+sin15)(sin75-sin15)=2*sin(75+15)/2*cos(75-15)/2*2*cos(75+15)*sin(75-15)/2=4*sin45*cos30*cos...
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