(1*2*4+2*4*8+……+n*2n*4n/1*3*9+2*6*18+……+n*3n*9n)^2
=[∑2^3(1^3+2^3+3^3+…+n^3)/∑3^3(1^3+2^3+3^3+…+n^3)]^2
=[(2/3)^3]^2)=(2/3)^6
=64/729=0.087791495