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∫(0,1)根号下[1-x^2]dx=
人气:496 ℃ 时间:2020-02-03 14:48:49
解答
令x=sint ,dx=costdt 当x=0时,t=0,当x=1时,t=π/2∫(0,1)根号下[1-x^2]dx= ∫(0,π/2)√(1-sin²t)costdt= ∫(0,π/2)√(1-sin²t)costdt=∫(0,π/2)cos²tdt =∫(0,π/2) [(cos2t +1)/2]dt=1/2∫(0,...
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