就是比如sin(2x-π/3),首先-π/2+2kπ≤x≤π/2+2kπ,然后是变成-π+2kπ≤x2≤π+2kπ还是-π+4kπ_数学解答

就是比如sin(2x-π/3),首先-π/2+2kπ≤x≤π/2+2kπ,然后是变成-π+2kπ≤x2≤π+2kπ
还是-π+4kπ≤x2≤π+4kπ,就是不等式两边同乘2后2kπ是变成4kπ还是保持原来的2kπ
.同样sin(x/2-π/3)两边同除2后2kπ是变成kπ还是保持原来的2kπ

人气：435 ℃　时间：2020-03-23 10:28:26

解答

sin(2x-π/3)的单调区间是-π/2+2kπ≤2x-π/3≤π/2+2kπ 然后变成-π/2+2kπ+π/3≤2x≤π/2+2kπ +π/3-π/4+kπ+π/6≤x≤π/4+kπ +π/6即-π/12+kπ≤x≤5π/12+kπsin(x/2-π/3)的单调区间是-π/2+2kπ≤x/2-...