x²(3x+5y)²-y²(5x+3y)²
=[x(3x+5y)]²-[y(5x+3y)]²
=(3x²+5xy)²-(5xy+3y²)²
=[(3x²+5xy)+(5xy+3y²)][(3x²+5xy)-(5xy+3y²)]
=(3x²+5xy+5xy+3y²)(3x²+5xy-5xy-3y²)
=(3x²+10xy+3y²)(3x²-3y²)
=3(3x+y)(x+3y)(x+y)(x-y)那么10xy到哪去了？(3x+y)(x+3y)=3x²+10xy+3y²