[13(x-3)-10(x-4)]/(x-4)(x-3)=[4(x-1)-(x-5)]/(x-5)(x-1)(3x+1)/(x-4)(x-3)=(3x+1)/(x-5)(x-1)(3x+1)(x-5)(x-1)=(3x+1)(x-4)(x-3)(3x+1)(x²-6x+5-x²+7x-12)=0(3x+1)(x-7)=0∴x=-1/3 x=7检验：