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1/3+1/15+1/35+1/63+1/99=?
人气:378 ℃ 时间:2019-12-01 14:02:38
解答
1/3+1/15+1/35+1/63+1/99
=1/2[(1-1/3)+(1/3-1/5)+(1/5-1/7)+(1/7-1/9)+(1/9-1/11)]
=1/2(1-1/11)
=1/2×10/11
=5/11 1/3+1/15+1/35+1/63+1/99
=1/2[(1-1/3)+(1/3-1/5)+(1/5-1/7)+(1/7-1/9)+(1/9-1/11)]
=1/2(1-1/11)
=1/2×10/11
1/3+1/15+1/35+1/63+1/99
=1/2[(1-1/3)+(1/3-1/5)+(1/5-1/7)+(1/7-1/9)+(1/9-1/11)]
=1/2(1-1/11)
=1/2×10/11
=5/11 =5/11 1/3+1/15+1/35+1/63+1/99
=1/2[(1-1/3)+(1/3-1/5)+(1/5-1/7)+(1/7-1/9)+(1/9-1/11)]
=1/2(1-1/11)
=1/2×10/11
1/3+1/15+1/35+1/63+1/99
=1/2[(1-1/3)+(1/3-1/5)+(1/5-1/7)+(1/7-1/9)+(1/9-1/11)]
=1/2(1-1/11)
=1/2×10/11
=5/11 =5/11
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