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方程lgx平方-lg(x+2)=0的解集是多少?
人气:480 ℃ 时间:2020-04-10 20:25:18
解答
lgx平方-lg(x+2)=0 ==> lg [x^2 / (x+2)] = 0 ==> x^2 / (x +2) = 1 ==> x^2 = x +2 ==> x^2 - x -2 = 0 ==> (x -2)(x +1) = 0 ==> x + 1 = 0 ==> x =2,-1
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