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因式分解 x^3-8y^3 等于什么
可以的话请写下公式
人气:489 ℃ 时间:2020-04-29 09:08:08
解答
直接用公式a^3-b^3=(a+b)(a^2+ab+b^2)
原式=x^3-(2y)^3
=(x+2y)[x^2+x*2y+(2y)^2]
=(x+2y)(x^2+2xy+4y^2)
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