∫((x+sinx)/(1+cosx))dx =∫[(x+sinx)/2cos²(x/2)]dx =∫(x+sinx)d(tan(x/2)) =(x+sinx)*tan(x/2)-∫tan(x/2)d(x+sinx) =xtan(x/2)+sinx*tan(x/2)-∫tan(x/2)(1+cosx)dx =xtan(x/2)+2sin(x/2)cos(x/2)*tan(x/2...