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已知sin(a+π/6)+cosa=4/5倍根号3,则sin(a+π/3)=
人气:183 ℃ 时间:2020-05-24 07:32:07
解答
sin(a+π/6)+cosa
=sina*(v3/2)+cosa*(1/2)+cosa
=v3[sina*(1/2)+cosa*(v3/2)]
=v3sin(a+π/3)
=(4/5)*v3,
——》sin(a+π/3)=4/5.
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