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为什么sin(a+b)-sina=2sin(b/2)cos(a+b/2)
人气:368 ℃ 时间:2020-06-13 07:58:00
解答
a+b=a+b/2+b/2,a=a+b/2-b/2sin(a+b)-sina=sin[(a+b/2)+(b/2)]-sin[(a+b/2)-(b/2)]展开=sin(a+b/2)*cosb/2+cos(a+b/2)*sinb/2-[sin(a+b/2)*cosb/2-cos(a+b/2)*sinb/2]=2sin(b/2)cos(a+b/2)...
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