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分解因式1.(x²+y²-z²)²-4x²y²2.x²-3x+6xy+9y²-9y
人气:152 ℃ 时间:2019-08-26 07:04:18
解答
1)(x²+y²-z²)²-4x²y²
=[(x²+y²-z²)+2xy][(x²+y²-z²)-2xy]
=[(x+y)²-z²][(x-y)²-z²]
=(x+y+z)(x+y-z)(x-y+z)(x-y-z)
2).x²-3x+6xy+9y²-9y
=(x+3y)²-3(x+3y)
=(x+3y)[(x+3y)-3]
=(x+3y)(x+3y-3)
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