> 数学 >
设f(x)在x0可导,则
lim
x→0
f(x0+x)−f(x0−3x)
x
等于(  )
A. 2f'(x0
B. f'(x0
C. 3f'(x0
D. 4f'(x0
人气:430 ℃ 时间:2019-08-21 07:21:15
解答
∵f(x)在x0可导,∴f′(x0)=
lim
x→0
f(x0+x)−f(x0)
x

lim
x→0
f(x0+x)−f(x0−3x)
x
=
lim
x→0
f(x0+x)−f(x0)+f(x0)−f(x0−3)
x

=
lim
x→0
f(x0+x)−f(x0)
x
+
lim
x→0
f(x0−3x)−f(x0)
−x
 
=f′(x0)+3
lim
x→0
f(x0−3x)−f(x0)
−3x
 
=f′(x0)+3f′(x0)=4f′(x0),
故选D.
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