已知m-n=2,mn=1,求多项式(2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值
人气:452 ℃ 时间:2019-09-21 02:31:57
解答
(2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)
先去括号
=2mn+2m+3n-3mn-2n+2m-m-4n-mn
合并同类项
=-2mn+3m-3n
=-2mn+3(m-n)
把m-n=2,mn=1代入
=-2*1+3*2
=-2+6
=4
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