在三角形ABC中,角C等于90度,BD平分角ABC,交AC于D,若DC等于3,求点D到AB的距离
人气:249 ℃ 时间:2019-08-17 00:15:58
解答
过点D做DE⊥AB
∵∠ABD = ∠CBD ∠C = ∠BDE =Rt∠ DB = DB
∴△DCB ≌△DEB
∴DC = DE=3
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