若x^2+n^2—6n+4m+13=0,则m-n
人气：428 ℃ 时间：2020-01-31 18:45:29
解答
原式=x²+n²-6n+4m+13
=x²+(n²-6n+9)+4m+4
=x²+(n-3)²+4(m+1)
即：x²+(n-3)²+4(m+1)=0
解得：x=0,n=3,m=-1
所以,m-n= -1 - 3 = -4
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