用因式分解法解下列方程:(1)x(x-3)-2(3-x)=0 (2)5x(x+2)=4x+8 (3)(x-1)²-25=0
人气:369 ℃ 时间:2019-08-21 21:02:12
解答
(1) x(x-3)-2(3-x)=0
x(x-3)+2(x-3)=0
(x-3)(x+2)=0
所以x=3或x=-2
(2)
5x^2+10x-4x-8=0
5x^2+6x-8=0
(x+2)(5x-4)=0
x1=-2,x2=4/5第三题呢?
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