当x=2007,y=2008时,求x^4-y^4/x^2-2xy-y^2÷x^2+y^2/y-x=
分式的计算
人气：171 ℃ 时间：2020-05-22 06:44:37
解答
(x^4-y^4)/(x^2-2xy+y^2)÷(x^2+y^2)/(y-x)= (x^2-y^2)(x^2+y^2)/(x^2-2xy+y^2)*(y-x)/(x^2+y^2)= (x^2-y^2)/(x^2-2xy+y^2)*(y-x)= (x-y)(x+y)/(x-y)^2*(y-x)= (x+y)/(x-y)*(y-x)= -(x+y)/(x-y)*(x-y)= -(x+y)=-x-y
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