(1)f(x)=sin(x+π/6)+sin(x-π/6)+cosx+a=根号3sinx+cosx+a=2sin(x+π/6)+a又因为函数f(x)=sin(x+π/6)+sin(x-π/6)+cosx+a的最大值为1所以,当且仅当sin(x+π/6)=1时,f(x)取得最大值,解得a=-1（2）(x+π/6)=1时,f(x)...