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(x-2)/(x+2)+16/(4-x^2)=(x+2)/(x-2)
人气:482 ℃ 时间:2020-04-04 17:22:45
解答
方程两边同时乘以4-x^2得,-(x-2)^2+16=-(x+2)^2,整理得
x^2=8,x=±2倍根号2,经检验,不是增根.计算(x^2-y^2)/xy-(xy-y^2)/xy-x^2答对+20分上一题,x=-2为增根,原方程没有实数根.(x^2-y^2)/xy-(xy-y^2)/xy-x^2=x/y-1-x^2不过你这道题是不是应为(x^2-y^2)/xy-(xy-y^2)/(xy-x^2)则结果为x/y-y/x-y(x-y)/x(y-x)=x/y-y/x+y/x=x/y
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