希望老师讲解
已知定义域为〔0,1〕的函数f(x)同时满足以下三个条件:
1、对任意的x∈〔0,1〕,总有f(x)≥0
2、f(1)=1
3、当x≥0 ,y≥0 ,且x+y《1时都有f(x+y)≥f(x)+f(y).
(1).试求f(0)的值
(2).求f(x)的最大值
(3)证明当x属于[1/4,1]时,恒有2x≥f(x)
人气:194 ℃ 时间:2020-05-10 19:33:16
解答
(1)
f(x+y)≥f(x)+f(y).
f(1)=f(1+0)≥f(0)+f(1)
∴f(0)≤0
又f(x)≥0恒成立
∴f(0)=0
(2)
取0≤m
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