答：
∫ [(e^x)^2/(2+e^x)] dx
= ∫ [e^x /(2+e^x)] d(e^x)
=∫ [(e^x+2-2)/ (2+e^x) ] d(e^x)
=∫ [1-2 / (e^x+2) ] d(e^x+2)
=e^x-2ln(e^x+2)+C