设y=f(x)由方程xe^y+ye^x=4xy确定,则dy/dx= 本人有e的导数不太会算
人气：331 ℃ 时间：2019-08-17 21:54:29
解答
(e^y+xe^y*y')+(y'e^x+ye^x)=4y+4xy'
(xe^y+e^x-4x)y'=4y-e^y-ye^x
y'=(4y-e^y-ye^x)/(xe^y+e^x-4x)
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