(2x-3y+b)(3x+y+c)
=(2x-3y)(3x+y)+b(3x+y)+c(2x-3y)+bc
=6x^2-7xy-3y^2+(3b+2c)x+(b-3c)y+bc
∵6x^2-7xy-3y^2+14x+y+a=(2x-3y+b)(3x+y+c)
14=3b+2c
1=b-3c
a=bc
∴a=4
b=4
c=1