这里假定"增加了2倍"为净增,即70℃时为60℃时的3倍(否则用k₂/k₁ = 2).
k = Ae(-Ea/RT)
k₂/k₁ = [Ae(-Ea/RT₂)]/[Ae(-Ea/RT₁)]
ln(k₂/k₁) = -Ea(1/T₂ - 1/T₁)/R = Ea(T₂ - T₁)/(RT₁T₂)
Ea = RT₁T₂[ln(k₂/k₁)]/(T₂ - T₁)
= 8.314*333*343*(ln3)/(343 - 333)
= 104000 J/mol
= 104 kJ/mol