
由上图可知,点(x,y)的坐标共有12种等可能的结果:
(1,-1),(1,-
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 3 |
(-2,
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2 |
其中点(x,y)落在第二象限的共有2种:(-2,
| 1 |
| 2 |
所以,P(x,y)落在第二象限=
| 2 |
| 12 |
| 1 |
| 6 |
或根据题意,画表格:
| 1 | -2 | 3 | |||||||||
| -1 | (1,-1) | (-2,-1) | (3,-1) | ||||||||
-
| (1,-
| (-2,-
| (3,-
| ||||||||
| (1,
| (-2,
| (3,
| ||||||||
| 2 | (1,2) | (-2,2) | (3,2) |
| 1 |
| 2 |
所以,P(点(x,y)落在第二象限)=
| 2 |
| 12 |
| 1 |
| 6 |
(2)P(点(x,y)落在y=-
| 1 |
| x |
| 3 |
| 12 |
| 1 |
| 4 |

