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lim(x趋向0)1-x^2-e^(-x^2)/xsin^3(2x)
人气:361 ℃ 时间:2020-03-23 01:35:07
解答
lim(x→0) [1-x^2-e^(-x^2)]/[xsin^3(2x)] =lim(x→0) [1-x^2-e^(-x^2)]/(8x^4) (0/0)=lim(x→0) [-2x+2xe^(-x^2)]/(32x^3) =lim(x→0) [-1+e^(-x^2)]/(16x^2) =lim(x→0) (-x^2)/(16x^2) =-1/16
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