答：x4(x-2y)+x2(2y-x) =(x-2y)(x^4-x^2)=(x-2y)(x^2-1)x^2=(x^2)*(x-2y)(x-1)(x+1)答：x^2(x-2y)=x^2(2y-x)(x-2y)x^2-(2y-x)x^2=0(x-2y)x^2+(x-2y)x^2=02(x-2y)x^2=0所以：x-2y=0或者x=0解得：x=0或者x=2y...x4(x-2y)+x2(2y-x) 因式分解答：

x4(x-2y)+x2(2y-x)
=(x-2y)(x^4-x^2)
=(x-2y)(x^2-1)x^2
=(x^2)*(x-2y)(x-1)(x+1)