为何(1/2)*(1/(n+1))*(1/(n+2))=(1/2)*((1/(n+1))-(1/(n+2)))*设为乘号_数学解答

为何(1/2)*(1/(n+1))*(1/(n+2))=(1/2)*((1/(n+1))-(1/(n+2)))
*设为乘号

人气：456 ℃　时间：2020-10-02 05:01:01

解答

这个是相等的啊,(1/n+1)-(1/(n+2)=((n+2)-(n+1))/(n+1)(n+2)=1/(n+1)(n+2)=(1/(n+1))*(1/(n+2))