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∫(1+x^3)^(3/2)*x^5dx
人气:173 ℃ 时间:2020-06-28 22:06:13
解答
u = 1+x³,du = 3x² dx∫ (1+x³)^(3/2) * x^5 dx= (1/3)∫ u^(3/2) * (u-1) du= (1/3)∫ [u^(5/2) - u^(3/2)] du= (1/3) * [u^(5/2+1) / (5/2+1) - u^(3/2+1) / (3/2+1)] + C= 2/21*(1+x³)^(7/2)...
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