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[tanx+(1/tanx)]cos^x
人气:125 ℃ 时间:2020-04-11 10:16:45
解答
=(sinx/cosx+cosx/sinx)cos²x
=[(sin²x+cos²x)/(sinxcosx)]*cos²x
=[1/(sinxcosx)]*cos²x
=cosx/sinx
=cotx
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