根据你的题目,我把你的式子改成标准写法：y=-sin(x/2)*(1-2（cos(x/4)^2))所以y'=-(1/2)*cos(x/2)*(1-2（cos(x/4)^2))-sin(x/2)*(-2*2cos(x/4)*（-sin(x/4))*(1/4))=-(1/2)*cos(x/2)*(1-2（cos(x/4)^2))-sin(x/2)*(c...