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已知:tanα=3,则sin平方α-cos平方α=
人气:111 ℃ 时间:2020-04-11 15:29:13
解答
sin²α-cos²α
=(sin²α-cos²α)/1
=(sin²α-cos²α)/(sin²α+cos²α)
=(tan²α-1)/(tan²α+1)
=(9-1)/(9+1)
=4/5
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