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求不定积分cos^2/sinx
人气:344 ℃ 时间:2020-05-29 12:12:11
解答
int cosx^2/sinx +sinx^2/sinx - sinx dx
= int 1/sinx - sinx d x
= int cscx dx + cosx
= log(tan(x/2)) + cosx + C
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