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已知等差数列{an}
S3:S6=1/3
S6:S12=?
人气:478 ℃ 时间:2020-05-14 03:08:52
解答
S3/S6=[(a1+a3)*3/2]/[(a1+a6)*6/2]=1/3
(9/2)(a1+a3)=3(a1+a6)
3(a1+a1+2d)=2(a1+a1+5d)
6a1+6d=4a1+10d
a1=2d
S6/S12=[(a1+a6)*6/2]/[(a1+a12)*12/2]
=(1/2)(a1+a1+5d)/(a1+a1+11d)
=(1/2)(4d+5d)/(4d+11d)
=3/5
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