因式分解(x-3y)^4+x^2-6xy+9y^2-2
答案不要有中括号,
人气:208 ℃ 时间:2020-02-03 20:41:52
解答
原式=(x-3y)^4+x^2-2*x*3y+(3y)^2-2 =(x-3y)^4+(x-3y)^2-2 =(x-3y)^4+2*1/2*(x-3y)^2+(1/2)^2-(1/2)^2-2 =[(x-3y)+1/2]^2-9/4 =(x-3y+1/2)^2-9/4=(x-3y+1/2+3/2)(x-3y+1/2-3/2)=(x-3y+2)(x-3y-1)
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