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将下列各式分解因式:
(1)x2-9y2
(2)x3-2x2y+xy2
(3)2x(a-b)-(b-a)
(4)x2-4y2-3x+6y.
人气:210 ℃ 时间:2020-03-25 00:34:07
解答
(1)x2-9y2=(x+3y)(x-3y);
(2)x3-2x2y+xy2=x(x2-2xy+y2)=x(x-y)2
(3)2x(a-b)-(b-a)=(a-b)(2x+1);
(4)x2-4y2-3x+6y=(x+2y)(x-2y)-3(x-2y)=(x-2y)(x+2y-3).
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