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sin^6a+cos^6a+3sin^2acos^2a的值为?
人气:312 ℃ 时间:2020-04-05 16:46:41
解答
sin^6a+cos^6a+3sin^2acos^2a=(sin²a+cos²a)(sin^4a-sin^2acos^2a+cos^4a)+3sin^2acos^2a=sin^4a-sin^2acos^2a+cos^4a+3sin^2acos^2a=sin^4a+2sin^2acos^2a+cos^4a=(sin²a+cos²a)²...
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