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计算lim(sinωx/x)在x→0的过程的极限
人气:399 ℃ 时间:2020-05-13 19:12:57
解答
lim(x->0) (sinωx/x)
= ω lim(x->0) (sinωx/ωx)
令:t = ωx ,x->0时,t->0
lim(x->0) (sinωx/ωx) = lim(t->0) sint/t = 1
= ω*1
= ω
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