设A={x|2x平方+ax+2=0},B={x|x平方+3x+2a=0},A∩B={2} 设全集U=A∪B,求(CuA)∪(CuB)
还有(CuA)∪(CuB)的所有子集
人气:426 ℃ 时间:2019-10-09 12:25:22
解答
因为A∩B={2}
所以2∈A且2∈B
所以2×2²+2a+2=0,2²+3×2+2a=0
解得a=-5
于是A={x|2x²-5x+2=0}={2,1/2}
B={x|x²+3x-10=0}={2,-5}
于是U=A∪B={2,1/2,-5}
CuA={-5},CuB={1/2}
(CuA)∪(CuB)={-5,1/2}
(CuA)∪(CuB)的所有子集为Φ(空集)、{-5}、{1/2}、{-5,1/2}
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